Sunday, June 1, 2008

The Way Democrats Count Every Vote

UPDATED WITH VIDEO.

Based on what the Press is reporting, about the Democrats' great compromise to allow the seating of the previously disenfranchised Florida and Michigan delegations, you may believe you understand that the Democrats reached a reasonable and fair compromise giving each Florida and Michigan delegate half a vote.

According to the press reports, the Democrats will allow each vote to count and still punish Florida and Michigan for violating the Party's rules about how soon primaries could be held.

That is what the Democrats did for Florida, but not Michigan.

No, for Michigan the Democrats decided to do a little of their creative counting of every vote.

According to CNN, Hillary managed to "win" the Michigan Primary:

Clinton - 55%
Uncommitted - 40%
Kucinich - 4%
Dodd - 1%
Gravel - 0%

Based upon the votes, Hillary earned 73 delegates and Obama none. Fifty five delegates should be uncommitted.

Instead of agreeing to seat a Michigan delegation based on the actual votes, the Democrats cut a deal to "let every vote count" that "allows" Hillary to have 69 delegates and gives Obama 59 delegates. That's right, even though Obama's name wasn't even on the ballot and therefore no one voted for him, the Democrats are giving him 59 delegates.

Watch Harold Ickes, one of Hillary's chief advisers, explain the undemocratic nature of the way the Democrats creatively counted Michigan votes:



The Rules and Bylaws Committee, 30 elite members of the Democrat Party substituted their judgment for 600,000 Michigan Voters and gave Obama four pledged delegates specifically won by Hillary and 55 delegates the voters said should be uncommitted.

Hillary supporters are not happy.

The Democrats' fuzzy math never ceases to amaze me. The way the Democrats decided to count every vote in Michigan reminds me of the way they tried to count Florida votes in 2000.

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